Base | Representation |
---|---|
bin | 11101010010110010101… |
… | …111001110110100101001 |
3 | 21010110000110100021002122 |
4 | 131102302233032310221 |
5 | 230440203103423312 |
6 | 4140440202441025 |
7 | 265303043514656 |
oct | 35226257166451 |
9 | 7113013307078 |
10 | 2013043420457 |
11 | 7067aa592713 |
12 | 286184203175 |
13 | 117aa1929744 |
14 | 6d608cbcc2d |
15 | 3756d159b72 |
hex | 1d4b2bced29 |
2013043420457 has 2 divisors, whose sum is σ = 2013043420458. Its totient is φ = 2013043420456.
The previous prime is 2013043420417. The next prime is 2013043420489. The reversal of 2013043420457 is 7540243403102.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1979004646441 + 34038774016 = 1406771^2 + 184496^2 .
It is a cyclic number.
It is not a de Polignac number, because 2013043420457 - 222 = 2013039226153 is a prime.
It is not a weakly prime, because it can be changed into another prime (2013043420417) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006521710228 + 1006521710229.
It is an arithmetic number, because the mean of its divisors is an integer number (1006521710229).
Almost surely, 22013043420457 is an apocalyptic number.
It is an amenable number.
2013043420457 is a deficient number, since it is larger than the sum of its proper divisors (1).
2013043420457 is an equidigital number, since it uses as much as digits as its factorization.
2013043420457 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 80640, while the sum is 35.
Adding to 2013043420457 its reverse (7540243403102), we get a palindrome (9553286823559).
The spelling of 2013043420457 in words is "two trillion, thirteen billion, forty-three million, four hundred twenty thousand, four hundred fifty-seven".
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