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2013043420457 is a prime number
BaseRepresentation
bin11101010010110010101…
…111001110110100101001
321010110000110100021002122
4131102302233032310221
5230440203103423312
64140440202441025
7265303043514656
oct35226257166451
97113013307078
102013043420457
117067aa592713
12286184203175
13117aa1929744
146d608cbcc2d
153756d159b72
hex1d4b2bced29

2013043420457 has 2 divisors, whose sum is σ = 2013043420458. Its totient is φ = 2013043420456.

The previous prime is 2013043420417. The next prime is 2013043420489. The reversal of 2013043420457 is 7540243403102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1979004646441 + 34038774016 = 1406771^2 + 184496^2 .

It is a cyclic number.

It is not a de Polignac number, because 2013043420457 - 222 = 2013039226153 is a prime.

It is not a weakly prime, because it can be changed into another prime (2013043420417) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006521710228 + 1006521710229.

It is an arithmetic number, because the mean of its divisors is an integer number (1006521710229).

Almost surely, 22013043420457 is an apocalyptic number.

It is an amenable number.

2013043420457 is a deficient number, since it is larger than the sum of its proper divisors (1).

2013043420457 is an equidigital number, since it uses as much as digits as its factorization.

2013043420457 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 80640, while the sum is 35.

Adding to 2013043420457 its reverse (7540243403102), we get a palindrome (9553286823559).

The spelling of 2013043420457 in words is "two trillion, thirteen billion, forty-three million, four hundred twenty thousand, four hundred fifty-seven".