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2013044641 = 14271410683
BaseRepresentation
bin111011111111100…
…1001111110100001
312012021220021002221
41313333021332201
513110314412031
6531430311041
7100612411546
oct16777117641
95167807087
102013044641
11943347263
124821b8481
1326109399a
141514d2bcd
15bbadca11
hex77fc9fa1

2013044641 has 4 divisors (see below), whose sum is σ = 2014456752. Its totient is φ = 2011632532.

The previous prime is 2013044633. The next prime is 2013044653. The reversal of 2013044641 is 1464403102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 1464403102 = 2732201551.

It is a cyclic number.

It is not a de Polignac number, because 2013044641 - 23 = 2013044633 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2013044041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 703915 + ... + 706768.

It is an arithmetic number, because the mean of its divisors is an integer number (503614188).

Almost surely, 22013044641 is an apocalyptic number.

It is an amenable number.

2013044641 is a deficient number, since it is larger than the sum of its proper divisors (1412111).

2013044641 is a wasteful number, since it uses less digits than its factorization.

2013044641 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1412110.

The product of its (nonzero) digits is 2304, while the sum is 25.

The square root of 2013044641 is about 44866.9660329289. The cubic root of 2013044641 is about 1262.6543190248.

Adding to 2013044641 its reverse (1464403102), we get a palindrome (3477447743).

The spelling of 2013044641 in words is "two billion, thirteen million, forty-four thousand, six hundred forty-one".

Divisors: 1 1427 1410683 2013044641