Base | Representation |
---|---|
bin | 1001001001111000111010… |
… | …00111000101001111111011 |
3 | 2122021111122000021201012022 |
4 | 10210330131013011033323 |
5 | 10114311242012041443 |
6 | 110452015341105055 |
7 | 4145262643425005 |
oct | 444743507051773 |
9 | 78244560251168 |
10 | 20131000112123 |
11 | 646156682720a |
12 | 231163325818b |
13 | b30464434794 |
14 | 4d84ba4a3375 |
15 | 24d9c08ede68 |
hex | 124f1d1c53fb |
20131000112123 has 2 divisors, whose sum is σ = 20131000112124. Its totient is φ = 20131000112122.
The previous prime is 20131000112089. The next prime is 20131000112149. The reversal of 20131000112123 is 32121100013102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20131000112123 - 218 = 20130999849979 is a prime.
It is not a weakly prime, because it can be changed into another prime (20131000112173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10065500056061 + 10065500056062.
It is an arithmetic number, because the mean of its divisors is an integer number (10065500056062).
Almost surely, 220131000112123 is an apocalyptic number.
20131000112123 is a deficient number, since it is larger than the sum of its proper divisors (1).
20131000112123 is an equidigital number, since it uses as much as digits as its factorization.
20131000112123 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 20131000112123 its reverse (32121100013102), we get a palindrome (52252100125225).
The spelling of 20131000112123 in words is "twenty trillion, one hundred thirty-one billion, one hundred twelve thousand, one hundred twenty-three".
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