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2013100414222 = 21006550207111
BaseRepresentation
bin11101010010110110001…
…000101001010100001110
321010110011102120211211211
4131102312020221110032
5230440312201223342
64140450000205034
7265304335121362
oct35226610512416
97113142524754
102013100414222
1170682977a9a7
1228619b30977a
13117ab0693271
146d6126b72a2
1537573166c17
hex1d4b622950e

2013100414222 has 4 divisors (see below), whose sum is σ = 3019650621336. Its totient is φ = 1006550207110.

The previous prime is 2013100414183. The next prime is 2013100414279. The reversal of 2013100414222 is 2224140013102.

It is a semiprime because it is the product of two primes.

It is a junction number, because it is equal to n+sod(n) for n = 2013100414193 and 2013100414202.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 503275103554 + ... + 503275103557.

It is an arithmetic number, because the mean of its divisors is an integer number (754912655334).

Almost surely, 22013100414222 is an apocalyptic number.

2013100414222 is a deficient number, since it is larger than the sum of its proper divisors (1006550207114).

2013100414222 is a wasteful number, since it uses less digits than its factorization.

2013100414222 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1006550207113.

The product of its (nonzero) digits is 768, while the sum is 22.

Adding to 2013100414222 its reverse (2224140013102), we get a palindrome (4237240427324).

The spelling of 2013100414222 in words is "two trillion, thirteen billion, one hundred million, four hundred fourteen thousand, two hundred twenty-two".

Divisors: 1 2 1006550207111 2013100414222