Base | Representation |
---|---|
bin | 11101010010110110001… |
… | …011010011110000001011 |
3 | 21010110011110220022110201 |
4 | 131102312023103300023 |
5 | 230440312341043311 |
6 | 4140450023153031 |
7 | 265304344056601 |
oct | 35226613236013 |
9 | 7113143808421 |
10 | 2013101112331 |
11 | 70682a107451 |
12 | 28619b5a5777 |
13 | 117ab0878c4a |
14 | 6d612819871 |
15 | 375732539c1 |
hex | 1d4b62d3c0b |
2013101112331 has 2 divisors, whose sum is σ = 2013101112332. Its totient is φ = 2013101112330.
The previous prime is 2013101112317. The next prime is 2013101112343. The reversal of 2013101112331 is 1332111013102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2013101112331 - 27 = 2013101112203 is a prime.
It is a super-2 number, since 2×20131011123312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2013101112299 and 2013101112308.
It is not a weakly prime, because it can be changed into another prime (2013101112301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006550556165 + 1006550556166.
It is an arithmetic number, because the mean of its divisors is an integer number (1006550556166).
Almost surely, 22013101112331 is an apocalyptic number.
2013101112331 is a deficient number, since it is larger than the sum of its proper divisors (1).
2013101112331 is an equidigital number, since it uses as much as digits as its factorization.
2013101112331 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 108, while the sum is 19.
Adding to 2013101112331 its reverse (1332111013102), we get a palindrome (3345212125433).
The spelling of 2013101112331 in words is "two trillion, thirteen billion, one hundred one million, one hundred twelve thousand, three hundred thirty-one".
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