201310144031 has 4 divisors (see below), whose sum is σ = 201311127000. Its totient is φ = 201309161064.

The previous prime is 201310143967. The next prime is 201310144037. The reversal of 201310144031 is 130441013102.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 130441013102 = 2 ⋅65220506551.

It is a cyclic number.

It is not a de Polignac number, because 201310144031 - 2⁶ = 201310143967 is a prime.

It is a super-2 number, since 2×201310144031² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 201310143994 and 201310144012.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (201310144037) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 55181 + ... + 636918.

It is an arithmetic number, because the mean of its divisors is an integer number (50327781750).

Almost surely, 2^201310144031 is an apocalyptic number.

201310144031 is a deficient number, since it is larger than the sum of its proper divisors (982969).

201310144031 is an equidigital number, since it uses as much as digits as its factorization.

201310144031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 982968.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 201310144031 its reverse (130441013102), we get a palindrome (331751157133).

The spelling of 201310144031 in words is "two hundred one billion, three hundred ten million, one hundred forty-four thousand, thirty-one".