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201310220143 = 17310139114769
BaseRepresentation
bin1011101101111100000…
…1100010111101101111
3201020121122200202122101
42323133001202331233
511244240404021033
6232251452355531
720354440431544
oct2733701427557
9636548622571
10201310220143
1178414409a6a
1233022475ba7
1315ca28c4c76
149a5a102bcb
1553834d297d
hex2edf062f6f

201310220143 has 8 divisors (see below), whose sum is σ = 202495597200. Its totient is φ = 200125093248.

The previous prime is 201310220107. The next prime is 201310220159. The reversal of 201310220143 is 341022013102.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 201310220143 - 233 = 192720285551 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 201310220143.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (201310227143) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1696663 + ... + 1811431.

It is an arithmetic number, because the mean of its divisors is an integer number (25311949650).

Almost surely, 2201310220143 is an apocalyptic number.

201310220143 is a deficient number, since it is larger than the sum of its proper divisors (1185377057).

201310220143 is a wasteful number, since it uses less digits than its factorization.

201310220143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 125081.

The product of its (nonzero) digits is 288, while the sum is 19.

Adding to 201310220143 its reverse (341022013102), we get a palindrome (542332233245).

The spelling of 201310220143 in words is "two hundred one billion, three hundred ten million, two hundred twenty thousand, one hundred forty-three".

Divisors: 1 173 10139 114769 1754047 19855037 1163642891 201310220143