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20131023211331 is a prime number
BaseRepresentation
bin1001001001111000111100…
…11111001100101101000011
32122021111200121202021100112
410210330132133030231003
510114311313420230311
6110452021524141535
74145263343652434
oct444743637145503
978244617667315
1020131023211331
116461578873a6a
12231163ab378ab
13b30469161756
144d84bd59748b
1524d9c296328b
hex124f1e7ccb43

20131023211331 has 2 divisors, whose sum is σ = 20131023211332. Its totient is φ = 20131023211330.

The previous prime is 20131023211297. The next prime is 20131023211363. The reversal of 20131023211331 is 13311232013102.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-20131023211331 is a prime.

It is a super-2 number, since 2×201310232113312 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 20131023211297 and 20131023211306.

It is not a weakly prime, because it can be changed into another prime (20131023211391) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10065511605665 + 10065511605666.

It is an arithmetic number, because the mean of its divisors is an integer number (10065511605666).

Almost surely, 220131023211331 is an apocalyptic number.

20131023211331 is a deficient number, since it is larger than the sum of its proper divisors (1).

20131023211331 is an equidigital number, since it uses as much as digits as its factorization.

20131023211331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 20131023211331 its reverse (13311232013102), we get a palindrome (33442255224433).

The spelling of 20131023211331 in words is "twenty trillion, one hundred thirty-one billion, twenty-three million, two hundred eleven thousand, three hundred thirty-one".