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201310401121 is a prime number
BaseRepresentation
bin1011101101111100001…
…0001111001001100001
3201020121200000221220021
42323133002033021201
511244240430313441
6232251500313441
720354442114304
oct2733702171141
9636550027807
10201310401121
1178414522a35
1233022542881
1315ca295945b
149a5a14cb3b
15538351b3d1
hex2edf08f261

201310401121 has 2 divisors, whose sum is σ = 201310401122. Its totient is φ = 201310401120.

The previous prime is 201310401079. The next prime is 201310401133. The reversal of 201310401121 is 121104013102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 152987370496 + 48323030625 = 391136^2 + 219825^2 .

It is a cyclic number.

It is not a de Polignac number, because 201310401121 - 221 = 201308303969 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 201310401095 and 201310401104.

It is not a weakly prime, because it can be changed into another prime (201310401421) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100655200560 + 100655200561.

It is an arithmetic number, because the mean of its divisors is an integer number (100655200561).

Almost surely, 2201310401121 is an apocalyptic number.

It is an amenable number.

201310401121 is a deficient number, since it is larger than the sum of its proper divisors (1).

201310401121 is an equidigital number, since it uses as much as digits as its factorization.

201310401121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 201310401121 its reverse (121104013102), we get a palindrome (322414414223).

The spelling of 201310401121 in words is "two hundred one billion, three hundred ten million, four hundred one thousand, one hundred twenty-one".