Base | Representation |
---|---|
bin | 11101010010110110010… |
… | …110011110101010001011 |
3 | 21010110011200102002021122 |
4 | 131102312112132222023 |
5 | 230440314113244322 |
6 | 4140450210025455 |
7 | 265304411004023 |
oct | 35226626365213 |
9 | 7113150362248 |
10 | 2013104040587 |
11 | 7068308274a2 |
12 | 2861a057828b |
13 | 117ab1362a43 |
14 | 6d612d7ca83 |
15 | 37573631442 |
hex | 1d4b659ea8b |
2013104040587 has 2 divisors, whose sum is σ = 2013104040588. Its totient is φ = 2013104040586.
The previous prime is 2013104040499. The next prime is 2013104040601. The reversal of 2013104040587 is 7850404013102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2013104040587 - 224 = 2013087263371 is a prime.
It is not a weakly prime, because it can be changed into another prime (2013104040887) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006552020293 + 1006552020294.
It is an arithmetic number, because the mean of its divisors is an integer number (1006552020294).
Almost surely, 22013104040587 is an apocalyptic number.
2013104040587 is a deficient number, since it is larger than the sum of its proper divisors (1).
2013104040587 is an equidigital number, since it uses as much as digits as its factorization.
2013104040587 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 26880, while the sum is 35.
Adding to 2013104040587 its reverse (7850404013102), we get a palindrome (9863508053689).
The spelling of 2013104040587 in words is "two trillion, thirteen billion, one hundred four million, forty thousand, five hundred eighty-seven".
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