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2013110303102 = 21006555151551
BaseRepresentation
bin11101010010110110101…
…110010111100101111110
321010110012010012020211122
4131102312232113211332
5230440322214144402
64140450552150542
7265304515146053
oct35226656274576
97113163166748
102013110303102
11706834314628
122861a2698452
13117ab2746382
146d613b2d02a
1537573e6bca2
hex1d4b6b9797e

2013110303102 has 4 divisors (see below), whose sum is σ = 3019665454656. Its totient is φ = 1006555151550.

The previous prime is 2013110303101. The next prime is 2013110303117. The reversal of 2013110303102 is 2013030113102.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×20131103031022 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2013110303101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 503277575774 + ... + 503277575777.

It is an arithmetic number, because the mean of its divisors is an integer number (754916363664).

Almost surely, 22013110303102 is an apocalyptic number.

2013110303102 is a deficient number, since it is larger than the sum of its proper divisors (1006555151554).

2013110303102 is a wasteful number, since it uses less digits than its factorization.

2013110303102 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1006555151553.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 2013110303102 its reverse (2013030113102), we get a palindrome (4026140416204).

The spelling of 2013110303102 in words is "two trillion, thirteen billion, one hundred ten million, three hundred three thousand, one hundred two".

Divisors: 1 2 1006555151551 2013110303102