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20131111424000 = 21253292715003
BaseRepresentation
bin1001001001111001000111…
…01111101101000000000000
32122021111220202201221101102
410210330203233231000000
510114312004011032000
6110452034354553532
74145265464522303
oct444744357550000
978244822657342
1020131111424000
1164616136444a5
1223116645988a8
13b30481508cb5
144d84cb19ab3a
1524d9ca58a3d5
hex124f23bed000

20131111424000 has 416 divisors, whose sum is σ = 52175784061440. Its totient is φ = 7744536576000.

The previous prime is 20131111423967. The next prime is 20131111424041. The reversal of 20131111424000 is 42411113102.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 4023805499 + ... + 4023810501.

It is an arithmetic number, because the mean of its divisors is an integer number (125422557840).

Almost surely, 220131111424000 is an apocalyptic number.

20131111424000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 20131111424000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (26087892030720).

20131111424000 is an abundant number, since it is smaller than the sum of its proper divisors (32044672637440).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

20131111424000 is an equidigital number, since it uses as much as digits as its factorization.

20131111424000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5342 (or 5310 counting only the distinct ones).

The product of its (nonzero) digits is 192, while the sum is 20.

Adding to 20131111424000 its reverse (42411113102), we get a palindrome (20173522537102).

The spelling of 20131111424000 in words is "twenty trillion, one hundred thirty-one billion, one hundred eleven million, four hundred twenty-four thousand".