20131112023333 has 4 divisors (see below), whose sum is σ = 20385936226240. Its totient is φ = 19876287820428.

The previous prime is 20131112023327. The next prime is 20131112023369. The reversal of 20131112023333 is 33332021113102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 20131112023333 - 2⁵ = 20131112023301 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 20131112023298 and 20131112023307.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20131112023433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 127412101335 + ... + 127412101492.

It is an arithmetic number, because the mean of its divisors is an integer number (5096484056560).

Almost surely, 2^{20131112023333} is an apocalyptic number.

It is an amenable number.

20131112023333 is a deficient number, since it is larger than the sum of its proper divisors (254824202907).

20131112023333 is an equidigital number, since it uses as much as digits as its factorization.

20131112023333 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 254824202906.

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 20131112023333 its reverse (33332021113102), we get a palindrome (53463133136435).

The spelling of 20131112023333 in words is "twenty trillion, one hundred thirty-one billion, one hundred twelve million, twenty-three thousand, three hundred thirty-three".