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20131112121 = 36710370707
BaseRepresentation
bin10010101111111010…
…000110010010111001
31220221222020110021020
4102233322012102321
5312212031041441
613125331333053
71311603425661
oct225772062271
956858213236
1020131112121
1185a054054a
123a99a51189
131b8a8c2683
14d8d8951a1
157cc518e66
hex4afe864b9

20131112121 has 4 divisors (see below), whose sum is σ = 26841482832. Its totient is φ = 13420741412.

The previous prime is 20131112117. The next prime is 20131112147. The reversal of 20131112121 is 12121113102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 20131112121 - 22 = 20131112117 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 20131112121.

It is not an unprimeable number, because it can be changed into a prime (20131112171) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3355185351 + ... + 3355185356.

It is an arithmetic number, because the mean of its divisors is an integer number (6710370708).

Almost surely, 220131112121 is an apocalyptic number.

It is an amenable number.

20131112121 is a deficient number, since it is larger than the sum of its proper divisors (6710370711).

20131112121 is an equidigital number, since it uses as much as digits as its factorization.

20131112121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6710370710.

The product of its (nonzero) digits is 24, while the sum is 15.

Adding to 20131112121 its reverse (12121113102), we get a palindrome (32252225223).

The spelling of 20131112121 in words is "twenty billion, one hundred thirty-one million, one hundred twelve thousand, one hundred twenty-one".

Divisors: 1 3 6710370707 20131112121