Base | Representation |
---|---|
bin | 10010101111111010… |
… | …000110010011010011 |
3 | 1220221222020110022012 |
4 | 102233322012103103 |
5 | 312212031042042 |
6 | 13125331333135 |
7 | 1311603426026 |
oct | 225772062323 |
9 | 56858213265 |
10 | 20131112147 |
11 | 85a0540573 |
12 | 3a99a511ab |
13 | 1b8a8c26a3 |
14 | d8d8951bd |
15 | 7cc518e82 |
hex | 4afe864d3 |
20131112147 has 2 divisors, whose sum is σ = 20131112148. Its totient is φ = 20131112146.
The previous prime is 20131112117. The next prime is 20131112153. The reversal of 20131112147 is 74121113102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20131112147 - 26 = 20131112083 is a prime.
It is not a weakly prime, because it can be changed into another prime (20131112117) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10065556073 + 10065556074.
It is an arithmetic number, because the mean of its divisors is an integer number (10065556074).
Almost surely, 220131112147 is an apocalyptic number.
20131112147 is a deficient number, since it is larger than the sum of its proper divisors (1).
20131112147 is an equidigital number, since it uses as much as digits as its factorization.
20131112147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 336, while the sum is 23.
Adding to 20131112147 its reverse (74121113102), we get a palindrome (94252225249).
The spelling of 20131112147 in words is "twenty billion, one hundred thirty-one million, one hundred twelve thousand, one hundred forty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •