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201311130143 = 1271585127009
BaseRepresentation
bin1011101101111100010…
…1000001001000011111
3201020121201101222221002
42323133011001020133
511244241122131033
6232251524100515
720354451241604
oct2733705011037
9636551358832
10201311130143
1178414980732
123302283473b
1315ca2b53226
149a5a29c6ab
1553836123e8
hex2edf14121f

201311130143 has 4 divisors (see below), whose sum is σ = 202896257280. Its totient is φ = 199726003008.

The previous prime is 201311130107. The next prime is 201311130151. The reversal of 201311130143 is 341031113102.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 341031113102 = 2170515556551.

It is a cyclic number.

It is not a de Polignac number, because 201311130143 - 212 = 201311126047 is a prime.

It is a super-2 number, since 2×2013111301432 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (201311130173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 792563378 + ... + 792563631.

It is an arithmetic number, because the mean of its divisors is an integer number (50724064320).

Almost surely, 2201311130143 is an apocalyptic number.

201311130143 is a deficient number, since it is larger than the sum of its proper divisors (1585127137).

201311130143 is a wasteful number, since it uses less digits than its factorization.

201311130143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1585127136.

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 201311130143 its reverse (341031113102), we get a palindrome (542342243245).

The spelling of 201311130143 in words is "two hundred one billion, three hundred eleven million, one hundred thirty thousand, one hundred forty-three".

Divisors: 1 127 1585127009 201311130143