Base | Representation |
---|---|
bin | 11101010010110110110… |
… | …100111000011001011010 |
3 | 21010110012020101222201022 |
4 | 131102312310320121122 |
5 | 230440323133312310 |
6 | 4140451052522442 |
7 | 265304535516311 |
oct | 35226664703132 |
9 | 7113166358638 |
10 | 2013112010330 |
11 | 706835280263 |
12 | 2861a3180422 |
13 | 117ab2bc3475 |
14 | 6d614055278 |
15 | 375741a7a55 |
hex | 1d4b6d3865a |
2013112010330 has 8 divisors (see below), whose sum is σ = 3623601618612. Its totient is φ = 805244804128.
The previous prime is 2013112010323. The next prime is 2013112010339. The reversal of 2013112010330 is 330102113102.
It can be written as a sum of positive squares in 2 ways, for example, as 1788577240129 + 224534770201 = 1337377^2 + 473851^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-2 number, since 2×20131120103302 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2013112010299 and 2013112010308.
It is not an unprimeable number, because it can be changed into a prime (2013112010339) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 100655600507 + ... + 100655600526.
Almost surely, 22013112010330 is an apocalyptic number.
2013112010330 is a deficient number, since it is larger than the sum of its proper divisors (1610489608282).
2013112010330 is a wasteful number, since it uses less digits than its factorization.
2013112010330 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 201311201040.
The product of its (nonzero) digits is 108, while the sum is 17.
Adding to 2013112010330 its reverse (330102113102), we get a palindrome (2343214123432).
The spelling of 2013112010330 in words is "two trillion, thirteen billion, one hundred twelve million, ten thousand, three hundred thirty".
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