Search a number
-
+
2013113302200 = 233252711131117279
BaseRepresentation
bin11101010010110110111…
…001110011110010111000
321010110012022211121211100
4131102312321303302320
5230440324001132300
64140451140331400
7265304552506560
oct35226671636270
97113168747740
102013113302200
11706835a82920
122861a36a3b60
13117ab32564a0
146d6142adda0
1537574360700
hex1d4b6e73cb8

2013113302200 has 576 divisors, whose sum is σ = 9077319014400. Its totient is φ = 386131276800.

The previous prime is 2013113302181. The next prime is 2013113302219. The reversal of 2013113302200 is 22033113102.

2013113302200 is a `hidden beast` number, since 2 + 0 + 1 + 311 + 330 + 2 + 20 + 0 = 666.

It is an interprime number because it is at equal distance from previous prime (2013113302181) and next prime (2013113302219).

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 143 ways as a sum of consecutive naturals, for example, 1243161 + ... + 2360439.

It is an arithmetic number, because the mean of its divisors is an integer number (15759234400).

Almost surely, 22013113302200 is an apocalyptic number.

2013113302200 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 2013113302200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (4538659507200).

2013113302200 is an abundant number, since it is smaller than the sum of its proper divisors (7064205712200).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

2013113302200 is a wasteful number, since it uses less digits than its factorization.

2013113302200 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1117332 (or 1117320 counting only the distinct ones).

The product of its (nonzero) digits is 216, while the sum is 18.

Adding to 2013113302200 its reverse (22033113102), we get a palindrome (2035146415302).

It can be divided in two parts, 20131 and 13302200, that added together give a palindrome (13322331).

The spelling of 2013113302200 in words is "two trillion, thirteen billion, one hundred thirteen million, three hundred two thousand, two hundred".