Base | Representation |
---|---|
bin | 10010101111111010… |
… | …011100010001001011 |
3 | 1220221222102000201122 |
4 | 102233322130101023 |
5 | 312212041431443 |
6 | 13125333305455 |
7 | 1311604252244 |
oct | 225772342113 |
9 | 56858360648 |
10 | 20131202123 |
11 | 85a05a212a |
12 | 3a99a9528b |
13 | 1b8a924626 |
14 | d8d8b9ccb |
15 | 7cc535968 |
hex | 4afe9c44b |
20131202123 has 2 divisors, whose sum is σ = 20131202124. Its totient is φ = 20131202122.
The previous prime is 20131202083. The next prime is 20131202129. The reversal of 20131202123 is 32120213102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20131202123 - 216 = 20131136587 is a prime.
It is not a weakly prime, because it can be changed into another prime (20131202129) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10065601061 + 10065601062.
It is an arithmetic number, because the mean of its divisors is an integer number (10065601062).
Almost surely, 220131202123 is an apocalyptic number.
20131202123 is a deficient number, since it is larger than the sum of its proper divisors (1).
20131202123 is an equidigital number, since it uses as much as digits as its factorization.
20131202123 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 20131202123 its reverse (32120213102), we get a palindrome (52251415225).
The spelling of 20131202123 in words is "twenty billion, one hundred thirty-one million, two hundred two thousand, one hundred twenty-three".
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