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201312103 = 580134703
BaseRepresentation
bin10111111111111…
…00011101100111
3112000210201021211
423333330131213
5403013441403
631550452251
74663060516
oct1377743547
9460721254
10201312103
11a36a9843
1257504087
13329265b5
141ca4467d
1512a1806d
hexbffc767

201312103 has 4 divisors (see below), whose sum is σ = 201352608. Its totient is φ = 201271600.

The previous prime is 201312061. The next prime is 201312107. The reversal of 201312103 is 301213102.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 301213102 = 2150606551.

It is a cyclic number.

It is not a de Polignac number, because 201312103 - 217 = 201181031 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (201312107) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11551 + ... + 23152.

It is an arithmetic number, because the mean of its divisors is an integer number (50338152).

Almost surely, 2201312103 is an apocalyptic number.

201312103 is a deficient number, since it is larger than the sum of its proper divisors (40505).

201312103 is an equidigital number, since it uses as much as digits as its factorization.

201312103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 40504.

The product of its (nonzero) digits is 36, while the sum is 13.

The square root of 201312103 is about 14188.4496334166. The cubic root of 201312103 is about 586.0796319231.

Adding to 201312103 its reverse (301213102), we get a palindrome (502525205).

Subtracting 201312103 from its reverse (301213102), we obtain a palindrome (99900999).

The spelling of 201312103 in words is "two hundred one million, three hundred twelve thousand, one hundred three".

Divisors: 1 5801 34703 201312103