Base | Representation |
---|---|
bin | 101101110001011110100111… |
… | …010111001101111001011001 |
3 | 222101210021000202002110001002 |
4 | 231301132213113031321121 |
5 | 202341244411310341441 |
6 | 1552053320202234345 |
7 | 60255220323346541 |
oct | 5561364727157131 |
9 | 871707022073032 |
10 | 201312220012121 |
11 | 5916503aaa8509 |
12 | 1a6b37a71b59b5 |
13 | 8843878c90c0a |
14 | 379d7c60dc321 |
15 | 18418d5be3b9b |
hex | b717a75cde59 |
201312220012121 has 2 divisors, whose sum is σ = 201312220012122. Its totient is φ = 201312220012120.
The previous prime is 201312220012109. The next prime is 201312220012129. The reversal of 201312220012121 is 121210022213102.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 104485931210896 + 96826288801225 = 10221836^2 + 9840035^2 .
It is a cyclic number.
It is not a de Polignac number, because 201312220012121 - 214 = 201312219995737 is a prime.
It is a super-2 number, since 2×2013122200121212 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 201312220012093 and 201312220012102.
It is not a weakly prime, because it can be changed into another prime (201312220012129) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100656110006060 + 100656110006061.
It is an arithmetic number, because the mean of its divisors is an integer number (100656110006061).
Almost surely, 2201312220012121 is an apocalyptic number.
It is an amenable number.
201312220012121 is a deficient number, since it is larger than the sum of its proper divisors (1).
201312220012121 is an equidigital number, since it uses as much as digits as its factorization.
201312220012121 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 192, while the sum is 20.
Adding to 201312220012121 its reverse (121210022213102), we get a palindrome (322522242225223).
The spelling of 201312220012121 in words is "two hundred one trillion, three hundred twelve billion, two hundred twenty million, twelve thousand, one hundred twenty-one".
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