Base | Representation |
---|---|
bin | 1011101101111100110… |
… | …0001010011000101011 |
3 | 201020121211221011002001 |
4 | 2323133030022120223 |
5 | 11244242112044201 |
6 | 232252032151431 |
7 | 20354503202146 |
oct | 2733714123053 |
9 | 636554834061 |
10 | 201313003051 |
11 | 78415a3a896 |
12 | 33023398577 |
13 | 15ca335a864 |
14 | 9a5a62905d |
15 | 5383882301 |
hex | 2edf30a62b |
201313003051 has 2 divisors, whose sum is σ = 201313003052. Its totient is φ = 201313003050.
The previous prime is 201313003033. The next prime is 201313003057. The reversal of 201313003051 is 150300313102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 201313003051 - 215 = 201312970283 is a prime.
It is not a weakly prime, because it can be changed into another prime (201313003057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100656501525 + 100656501526.
It is an arithmetic number, because the mean of its divisors is an integer number (100656501526).
Almost surely, 2201313003051 is an apocalyptic number.
201313003051 is a deficient number, since it is larger than the sum of its proper divisors (1).
201313003051 is an equidigital number, since it uses as much as digits as its factorization.
201313003051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 270, while the sum is 19.
Adding to 201313003051 its reverse (150300313102), we get a palindrome (351613316153).
The spelling of 201313003051 in words is "two hundred one billion, three hundred thirteen million, three thousand, fifty-one".
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