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201313112301102 = 23314063106832659
BaseRepresentation
bin101101110001011111011100…
…100011000001111000101110
3222101210100022221002102102010
4231301133130203001320232
5202341303223222113402
61552053544515142050
760255251406601254
oct5561373443017056
9871710287072363
10201313112301102
115916545874341a
121a6b39b5ba4926
13884398bab7869
14379d86c80c5d4
1518419391eaa6c
hexb717dc8c1e2e

201313112301102 has 16 divisors (see below), whose sum is σ = 402627510362880. Its totient is φ = 67104156473592.

The previous prime is 201313112301073. The next prime is 201313112301127. The reversal of 201313112301102 is 201103211313102.

It is a super-2 number, since 2×2013131123011022 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 51531952 + ... + 55300707.

It is an arithmetic number, because the mean of its divisors is an integer number (25164219397680).

Almost surely, 2201313112301102 is an apocalyptic number.

201313112301102 is an abundant number, since it is smaller than the sum of its proper divisors (201314398061778).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

201313112301102 is a wasteful number, since it uses less digits than its factorization.

201313112301102 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 107146727.

The product of its (nonzero) digits is 216, while the sum is 21.

Adding to 201313112301102 its reverse (201103211313102), we get a palindrome (402416323614204).

The spelling of 201313112301102 in words is "two hundred one trillion, three hundred thirteen billion, one hundred twelve million, three hundred one thousand, one hundred two".

Divisors: 1 2 3 6 314063 628126 942189 1884378 106832659 213665318 320497977 640995954 33552185383517 67104370767034 100656556150551 201313112301102