Base | Representation |
---|---|
bin | 101101110001011111100001… |
… | …111000100101011110100011 |
3 | 222101210100120011120100221001 |
4 | 231301133201320211132203 |
5 | 202341303414132303422 |
6 | 1552054001434212431 |
7 | 60255253544624611 |
oct | 5561374170453643 |
9 | 871710504510831 |
10 | 201313201837987 |
11 | 591654a4238848 |
12 | 1a6b3a1bb84117 |
13 | 88439a4506a75 |
14 | 379d87a6786b1 |
15 | 1841941ed5227 |
hex | b717e1e257a3 |
201313201837987 has 2 divisors, whose sum is σ = 201313201837988. Its totient is φ = 201313201837986.
The previous prime is 201313201837877. The next prime is 201313201838011. The reversal of 201313201837987 is 789738102313102.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-201313201837987 is a prime.
It is not a weakly prime, because it can be changed into another prime (201313201837687) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100656600918993 + 100656600918994.
It is an arithmetic number, because the mean of its divisors is an integer number (100656600918994).
Almost surely, 2201313201837987 is an apocalyptic number.
201313201837987 is a deficient number, since it is larger than the sum of its proper divisors (1).
201313201837987 is an equidigital number, since it uses as much as digits as its factorization.
201313201837987 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3048192, while the sum is 55.
The spelling of 201313201837987 in words is "two hundred one trillion, three hundred thirteen billion, two hundred one million, eight hundred thirty-seven thousand, nine hundred eighty-seven".
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