Base | Representation |
---|---|
bin | 101101110001011111100001… |
… | …111001100101011110001011 |
3 | 222101210100120012001200111012 |
4 | 231301133201321211132023 |
5 | 202341303414214200412 |
6 | 1552054001443554135 |
7 | 60255253550066036 |
oct | 5561374171453613 |
9 | 871710505050435 |
10 | 201313202100107 |
11 | 591654a43a7779 |
12 | 1a6b3a2008b94b |
13 | 88439a4599176 |
14 | 379d87a70601d |
15 | 1841942037c22 |
hex | b717e1e6578b |
201313202100107 has 2 divisors, whose sum is σ = 201313202100108. Its totient is φ = 201313202100106.
The previous prime is 201313202100079. The next prime is 201313202100163. The reversal of 201313202100107 is 701001202313102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 201313202100107 - 242 = 196915155589003 is a prime.
It is a super-2 number, since 2×2013132021001072 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (201313202100707) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100656601050053 + 100656601050054.
It is an arithmetic number, because the mean of its divisors is an integer number (100656601050054).
Almost surely, 2201313202100107 is an apocalyptic number.
201313202100107 is a deficient number, since it is larger than the sum of its proper divisors (1).
201313202100107 is an equidigital number, since it uses as much as digits as its factorization.
201313202100107 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 504, while the sum is 23.
Adding to 201313202100107 its reverse (701001202313102), we get a palindrome (902314404413209).
The spelling of 201313202100107 in words is "two hundred one trillion, three hundred thirteen billion, two hundred two million, one hundred thousand, one hundred seven".
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