Base | Representation |
---|---|
bin | 11101010010111000000… |
… | …110001000110010010011 |
3 | 21010110020201111011220120 |
4 | 131102320012020302103 |
5 | 230440344111423443 |
6 | 4140453133241323 |
7 | 265305214543614 |
oct | 35227006106223 |
9 | 7113221434816 |
10 | 2013133311123 |
11 | 7068462a9920 |
12 | 2861aa333243 |
13 | 117ab744099c |
14 | 6d616bdbc0b |
15 | 37575eb4083 |
hex | 1d4b8188c93 |
2013133311123 has 16 divisors (see below), whose sum is σ = 2928233193600. Its totient is φ = 1220064425280.
The previous prime is 2013133311113. The next prime is 2013133311149. The reversal of 2013133311123 is 3211133313102.
It is not a de Polignac number, because 2013133311123 - 212 = 2013133307027 is a prime.
It is a super-2 number, since 2×20131333111232 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2013133311093 and 2013133311102.
It is not an unprimeable number, because it can be changed into a prime (2013133311113) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2369223 + ... + 3104751.
It is an arithmetic number, because the mean of its divisors is an integer number (183014574600).
Almost surely, 22013133311123 is an apocalyptic number.
2013133311123 is a deficient number, since it is larger than the sum of its proper divisors (915099882477).
2013133311123 is a wasteful number, since it uses less digits than its factorization.
2013133311123 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 818482.
The product of its (nonzero) digits is 972, while the sum is 24.
Adding to 2013133311123 its reverse (3211133313102), we get a palindrome (5224266624225).
The spelling of 2013133311123 in words is "two trillion, thirteen billion, one hundred thirty-three million, three hundred eleven thousand, one hundred twenty-three".
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