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201313433401 = 2001831005647
BaseRepresentation
bin1011101101111100110…
…1110011011100111001
3201020121212202000101221
42323133031303130321
511244242214332101
6232252045312041
720354506643623
oct2733715633471
9636555660357
10201313433401
1178416204153
1233023565621
1315ca347b6c2
149a5a6dbc13
155383919aa1
hex2edf373739

201313433401 has 4 divisors (see below), whose sum is σ = 201314639232. Its totient is φ = 201312227572.

The previous prime is 201313433393. The next prime is 201313433429. The reversal of 201313433401 is 104334313102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 104334313102 = 252167156551.

It is a cyclic number.

It is not a de Polignac number, because 201313433401 - 23 = 201313433393 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (201313433201) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 302641 + ... + 703006.

It is an arithmetic number, because the mean of its divisors is an integer number (50328659808).

Almost surely, 2201313433401 is an apocalyptic number.

It is an amenable number.

201313433401 is a deficient number, since it is larger than the sum of its proper divisors (1205831).

201313433401 is a wasteful number, since it uses less digits than its factorization.

201313433401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1205830.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 201313433401 its reverse (104334313102), we get a palindrome (305647746503).

The spelling of 201313433401 in words is "two hundred one billion, three hundred thirteen million, four hundred thirty-three thousand, four hundred one".

Divisors: 1 200183 1005647 201313433401