Search a number
-
+
201313633431312 = 2435176834459409
BaseRepresentation
bin101101110001011111111011…
…100110111110111100010000
3222101210101200020200120200000
4231301133323212332330100
5202341310310124300222
61552054112332530000
760255300335252313
oct5561377346767420
9871711606616600
10201313633431312
11591656a5922246
121a6b3b20620900
138843a42a5a62c
14379d8bbb0497a
151841969d399ac
hexb717fb9bef10

201313633431312 has 240 divisors, whose sum is σ = 619539623801280. Its totient is φ = 63064733884416.

The previous prime is 201313633431271. The next prime is 201313633431319. The reversal of 201313633431312 is 213134336313102.

201313633431312 is a `hidden beast` number, since 2 + 0 + 1 + 3 + 1 + 3 + 6 + 334 + 3 + 1 + 312 = 666.

It is a Harshad number since it is a multiple of its sum of digits (36).

It is not an unprimeable number, because it can be changed into a prime (201313633431319) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 42913864 + ... + 47373272.

It is an arithmetic number, because the mean of its divisors is an integer number (2581415099172).

Almost surely, 2201313633431312 is an apocalyptic number.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 201313633431312, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (309769811900640).

201313633431312 is an abundant number, since it is smaller than the sum of its proper divisors (418225990369968).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

201313633431312 is a wasteful number, since it uses less digits than its factorization.

201313633431312 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4460132 (or 4460114 counting only the distinct ones).

The product of its (nonzero) digits is 69984, while the sum is 36.

Adding to 201313633431312 its reverse (213134336313102), we get a palindrome (414447969744414).

The spelling of 201313633431312 in words is "two hundred one trillion, three hundred thirteen billion, six hundred thirty-three million, four hundred thirty-one thousand, three hundred twelve".