Base | Representation |
---|---|
bin | 10010101111111011… |
… | …001111000011001001 |
3 | 1220221222210121001021 |
4 | 102233323033003021 |
5 | 312212120110441 |
6 | 13125341552441 |
7 | 1311606106534 |
oct | 225773170311 |
9 | 56858717037 |
10 | 20131410121 |
11 | 85a0724429 |
12 | 3a99b75721 |
13 | 1b8a9981c4 |
14 | d8d931a1b |
15 | 7cc5773d1 |
hex | 4afecf0c9 |
20131410121 has 2 divisors, whose sum is σ = 20131410122. Its totient is φ = 20131410120.
The previous prime is 20131410113. The next prime is 20131410127. The reversal of 20131410121 is 12101413102.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12827827600 + 7303582521 = 113260^2 + 85461^2 .
It is a cyclic number.
It is not a de Polignac number, because 20131410121 - 23 = 20131410113 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 20131410095 and 20131410104.
It is not a weakly prime, because it can be changed into another prime (20131410127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10065705060 + 10065705061.
It is an arithmetic number, because the mean of its divisors is an integer number (10065705061).
Almost surely, 220131410121 is an apocalyptic number.
It is an amenable number.
20131410121 is a deficient number, since it is larger than the sum of its proper divisors (1).
20131410121 is an equidigital number, since it uses as much as digits as its factorization.
20131410121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 20131410121 its reverse (12101413102), we get a palindrome (32232823223).
The spelling of 20131410121 in words is "twenty billion, one hundred thirty-one million, four hundred ten thousand, one hundred twenty-one".
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