Base | Representation |
---|---|
bin | 1001001001111001101101… |
… | …11010111000010011101001 |
3 | 2122021112202012001211201011 |
4 | 10210330312322320103221 |
5 | 10114313133334333001 |
6 | 110452130330023521 |
7 | 4145306452066366 |
oct | 444746672702351 |
9 | 78245665054634 |
10 | 20131433121001 |
11 | 6461769198194 |
12 | 2311734277ba1 |
13 | b30503062757 |
14 | 4d851bbbb46d |
15 | 24d9e8932d51 |
hex | 124f36eb84e9 |
20131433121001 has 2 divisors, whose sum is σ = 20131433121002. Its totient is φ = 20131433121000.
The previous prime is 20131433120957. The next prime is 20131433121011. The reversal of 20131433121001 is 10012133413102.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 18552841904601 + 1578591216400 = 4307301^2 + 1256420^2 .
It is a cyclic number.
It is not a de Polignac number, because 20131433121001 - 29 = 20131433120489 is a prime.
It is not a weakly prime, because it can be changed into another prime (20131433121011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10065716560500 + 10065716560501.
It is an arithmetic number, because the mean of its divisors is an integer number (10065716560501).
Almost surely, 220131433121001 is an apocalyptic number.
It is an amenable number.
20131433121001 is a deficient number, since it is larger than the sum of its proper divisors (1).
20131433121001 is an equidigital number, since it uses as much as digits as its factorization.
20131433121001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 20131433121001 its reverse (10012133413102), we get a palindrome (30143566534103).
The spelling of 20131433121001 in words is "twenty trillion, one hundred thirty-one billion, four hundred thirty-three million, one hundred twenty-one thousand, one".
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