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2013200140453 = 3431958661387
BaseRepresentation
bin11101010010111100000…
…101000100100010100101
321010110102101020110111221
4131102330011010202211
5230441013213443303
64140503521500341
7265306655563405
oct35227405044245
97113371213457
102013200140453
1170687aaa4777
122862087a16b1
13117ac823c278
146d621a36805
153757bcb54bd
hex1d4bc1448a5

2013200140453 has 4 divisors (see below), whose sum is σ = 2013258836160. Its totient is φ = 2013141444748.

The previous prime is 2013200140439. The next prime is 2013200140463. The reversal of 2013200140453 is 3540410023102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2013200140453 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2013200140463) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29296375 + ... + 29365012.

It is an arithmetic number, because the mean of its divisors is an integer number (503314709040).

Almost surely, 22013200140453 is an apocalyptic number.

It is an amenable number.

2013200140453 is a deficient number, since it is larger than the sum of its proper divisors (58695707).

2013200140453 is an equidigital number, since it uses as much as digits as its factorization.

2013200140453 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 58695706.

The product of its (nonzero) digits is 2880, while the sum is 25.

Adding to 2013200140453 its reverse (3540410023102), we get a palindrome (5553610163555).

The spelling of 2013200140453 in words is "two trillion, thirteen billion, two hundred million, one hundred forty thousand, four hundred fifty-three".

Divisors: 1 34319 58661387 2013200140453