Base | Representation |
---|---|
bin | 11101010010111100001… |
… | …100100111110101010111 |
3 | 21010110102111222000222100 |
4 | 131102330030213311113 |
5 | 230441014220320043 |
6 | 4140504032133143 |
7 | 265310011446633 |
oct | 35227414476527 |
9 | 7113374860870 |
10 | 2013202120023 |
11 | 706881126a86 |
12 | 2862093971b3 |
13 | 117ac8783303 |
14 | 6d621dcddc3 |
15 | 3757c056cd3 |
hex | 1d4bc327d57 |
2013202120023 has 48 divisors (see below), whose sum is σ = 3294200988000. Its totient is φ = 1177084016640.
The previous prime is 2013202119997. The next prime is 2013202120037. The reversal of 2013202120023 is 3200212023102.
2013202120023 is a `hidden beast` number, since 201 + 320 + 2 + 120 + 0 + 23 = 666.
It is not a de Polignac number, because 2013202120023 - 28 = 2013202119767 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2013202119978 and 2013202120005.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2013202128023) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 5499198 + ... + 5853851.
It is an arithmetic number, because the mean of its divisors is an integer number (68629187250).
Almost surely, 22013202120023 is an apocalyptic number.
2013202120023 is a deficient number, since it is larger than the sum of its proper divisors (1280998867977).
2013202120023 is a wasteful number, since it uses less digits than its factorization.
2013202120023 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11353152 (or 11353149 counting only the distinct ones).
The product of its (nonzero) digits is 288, while the sum is 18.
Adding to 2013202120023 its reverse (3200212023102), we get a palindrome (5213414143125).
The spelling of 2013202120023 in words is "two trillion, thirteen billion, two hundred two million, one hundred twenty thousand, twenty-three".
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