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20132110111 = 65473075013
BaseRepresentation
bin10010101111111101…
…111001111100011111
31220222001010011020211
4102233331321330133
5312212310010421
613125404553251
71311615053401
oct225775717437
956861104224
1020132110111
1185a1062333
123a9a252827
131b8ab819b9
14d8da74b71
157cc6649e1
hex4aff79f1f

20132110111 has 4 divisors (see below), whose sum is σ = 20135191672. Its totient is φ = 20129028552.

The previous prime is 20132110109. The next prime is 20132110129. The reversal of 20132110111 is 11101123102.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 20132110111 - 21 = 20132110109 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 20132110091 and 20132110100.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20132110511) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1530960 + ... + 1544053.

It is an arithmetic number, because the mean of its divisors is an integer number (5033797918).

Almost surely, 220132110111 is an apocalyptic number.

20132110111 is a deficient number, since it is larger than the sum of its proper divisors (3081561).

20132110111 is an equidigital number, since it uses as much as digits as its factorization.

20132110111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3081560.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 20132110111 its reverse (11101123102), we get a palindrome (31233233213).

The spelling of 20132110111 in words is "twenty billion, one hundred thirty-two million, one hundred ten thousand, one hundred eleven".

Divisors: 1 6547 3075013 20132110111