Base | Representation |
---|---|
bin | 11101010010111100110… |
… | …010010110100111111011 |
3 | 21010110110012120112211221 |
4 | 131102330302112213323 |
5 | 230441024233323003 |
6 | 4140505024132511 |
7 | 265310161513414 |
oct | 35227462264773 |
9 | 7113405515757 |
10 | 2013212011003 |
11 | 706886772246 |
12 | 286210767137 |
13 | 117aca83736b |
14 | 6d62344680b |
15 | 3757cd5c7bd |
hex | 1d4bcc969fb |
2013212011003 has 2 divisors, whose sum is σ = 2013212011004. Its totient is φ = 2013212011002.
The previous prime is 2013212010973. The next prime is 2013212011073. The reversal of 2013212011003 is 3001102123102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2013212011003 - 225 = 2013178456571 is a prime.
It is not a weakly prime, because it can be changed into another prime (2013212011073) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006606005501 + 1006606005502.
It is an arithmetic number, because the mean of its divisors is an integer number (1006606005502).
Almost surely, 22013212011003 is an apocalyptic number.
2013212011003 is a deficient number, since it is larger than the sum of its proper divisors (1).
2013212011003 is an equidigital number, since it uses as much as digits as its factorization.
2013212011003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 2013212011003 its reverse (3001102123102), we get a palindrome (5014314134105).
The spelling of 2013212011003 in words is "two trillion, thirteen billion, two hundred twelve million, eleven thousand, three".
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