Base | Representation |
---|---|
bin | 11101010010111100110… |
… | …011100010100110010001 |
3 | 21010110110020011100201111 |
4 | 131102330303202212101 |
5 | 230441024323302233 |
6 | 4140505034533321 |
7 | 265310164250602 |
oct | 35227463424621 |
9 | 7113406140644 |
10 | 2013212322193 |
11 | 706886965026 |
12 | 286210897241 |
13 | 117aca915bb7 |
14 | 6d6234c7da9 |
15 | 3757cdbeacd |
hex | 1d4bcce2991 |
2013212322193 has 2 divisors, whose sum is σ = 2013212322194. Its totient is φ = 2013212322192.
The previous prime is 2013212322179. The next prime is 2013212322217. The reversal of 2013212322193 is 3912232123102.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1396159654464 + 617052667729 = 1181592^2 + 785527^2 .
It is a cyclic number.
It is not a de Polignac number, because 2013212322193 - 25 = 2013212322161 is a prime.
It is not a weakly prime, because it can be changed into another prime (2013212322893) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006606161096 + 1006606161097.
It is an arithmetic number, because the mean of its divisors is an integer number (1006606161097).
Almost surely, 22013212322193 is an apocalyptic number.
It is an amenable number.
2013212322193 is a deficient number, since it is larger than the sum of its proper divisors (1).
2013212322193 is an equidigital number, since it uses as much as digits as its factorization.
2013212322193 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7776, while the sum is 31.
Adding to 2013212322193 its reverse (3912232123102), we get a palindrome (5925444445295).
The spelling of 2013212322193 in words is "two trillion, thirteen billion, two hundred twelve million, three hundred twenty-two thousand, one hundred ninety-three".
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