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201321312231000 = 233531328118370409
BaseRepresentation
bin101101110001100111000101…
…010011010001111001011000
3222101211010111101201000120110
4231301213011103101321120
5202341422021412343000
61552101422320124320
760255661536054363
oct5561470523217130
9871733441630513
10201321312231000
1159168986356095
121a6b55041666a0
13884469788c0a0
1437a000987b0da
151841c69039850
hexb719c54d1e58

201321312231000 has 256 divisors, whose sum is σ = 678846904444800. Its totient is φ = 49379656704000.

The previous prime is 201321312230953. The next prime is 201321312231037. The reversal of 201321312231000 is 132213123102.

201321312231000 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a super-2 number, since 2×2013213122310002 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1773796 + ... + 20144204.

Almost surely, 2201321312231000 is an apocalyptic number.

201321312231000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 201321312231000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (339423452222400).

201321312231000 is an abundant number, since it is smaller than the sum of its proper divisors (477525592213800).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

201321312231000 is a wasteful number, since it uses less digits than its factorization.

201321312231000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 18370727 (or 18370713 counting only the distinct ones).

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 201321312231000 its reverse (132213123102), we get a palindrome (201453525354102).

The spelling of 201321312231000 in words is "two hundred one trillion, three hundred twenty-one billion, three hundred twelve million, two hundred thirty-one thousand".