Base | Representation |
---|---|
bin | 101101110001101000000001… |
… | …010111101100011100111011 |
3 | 222101211020002122001001222101 |
4 | 231301220001113230130323 |
5 | 202341431102411140212 |
6 | 1552102110320404231 |
7 | 60256025524122502 |
oct | 5561500127543473 |
9 | 871736078031871 |
10 | 201322320021307 |
11 | 5916935320a941 |
12 | 1a6b5745776677 |
13 | 88447c85c6104 |
14 | 37a00a3655839 |
15 | 1841cc7759157 |
hex | b71a015ec73b |
201322320021307 has 2 divisors, whose sum is σ = 201322320021308. Its totient is φ = 201322320021306.
The previous prime is 201322320021301. The next prime is 201322320021367. The reversal of 201322320021307 is 703120023223102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 201322320021307 - 23 = 201322320021299 is a prime.
It is not a weakly prime, because it can be changed into another prime (201322320021301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100661160010653 + 100661160010654.
It is an arithmetic number, because the mean of its divisors is an integer number (100661160010654).
Almost surely, 2201322320021307 is an apocalyptic number.
201322320021307 is a deficient number, since it is larger than the sum of its proper divisors (1).
201322320021307 is an equidigital number, since it uses as much as digits as its factorization.
201322320021307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6048, while the sum is 28.
Adding to 201322320021307 its reverse (703120023223102), we get a palindrome (904442343244409).
The spelling of 201322320021307 in words is "two hundred one trillion, three hundred twenty-two billion, three hundred twenty million, twenty-one thousand, three hundred seven".
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