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2013230132101 = 4634348229227
BaseRepresentation
bin11101010010111101110…
…111011110101110000101
321010110111110200012022201
4131102331313132232011
5230441043403211401
64140510512354501
7265310501525536
oct35227567365605
97113443605281
102013230132101
11706895a19961
12286216845a31
13117b015104c6
146d625a0268d
153757e73bb01
hex1d4bdddeb85

2013230132101 has 4 divisors (see below), whose sum is σ = 2017578361792. Its totient is φ = 2008881902412.

The previous prime is 2013230132059. The next prime is 2013230132119. The reversal of 2013230132101 is 1012310323102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2013230132101 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2013230102101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2174114151 + ... + 2174115076.

It is an arithmetic number, because the mean of its divisors is an integer number (504394590448).

Almost surely, 22013230132101 is an apocalyptic number.

It is an amenable number.

2013230132101 is a deficient number, since it is larger than the sum of its proper divisors (4348229691).

2013230132101 is an equidigital number, since it uses as much as digits as its factorization.

2013230132101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4348229690.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 2013230132101 its reverse (1012310323102), we get a palindrome (3025540455203).

The spelling of 2013230132101 in words is "two trillion, thirteen billion, two hundred thirty million, one hundred thirty-two thousand, one hundred one".

Divisors: 1 463 4348229227 2013230132101