Base | Representation |
---|---|
bin | 11101010010111101110… |
… | …111011110101110010111 |
3 | 21010110111110200012100101 |
4 | 131102331313132232113 |
5 | 230441043403211434 |
6 | 4140510512354531 |
7 | 265310501525563 |
oct | 35227567365627 |
9 | 7113443605311 |
10 | 2013230132119 |
11 | 706895a19978 |
12 | 286216845a47 |
13 | 117b0151050b |
14 | 6d625a026a3 |
15 | 3757e73bb14 |
hex | 1d4bdddeb97 |
2013230132119 has 2 divisors, whose sum is σ = 2013230132120. Its totient is φ = 2013230132118.
The previous prime is 2013230132059. The next prime is 2013230132143. The reversal of 2013230132119 is 9112310323102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2013230132119 - 29 = 2013230131607 is a prime.
It is a super-2 number, since 2×20132301321192 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2013230172119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006615066059 + 1006615066060.
It is an arithmetic number, because the mean of its divisors is an integer number (1006615066060).
Almost surely, 22013230132119 is an apocalyptic number.
2013230132119 is a deficient number, since it is larger than the sum of its proper divisors (1).
2013230132119 is an equidigital number, since it uses as much as digits as its factorization.
2013230132119 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1944, while the sum is 28.
The spelling of 2013230132119 in words is "two trillion, thirteen billion, two hundred thirty million, one hundred thirty-two thousand, one hundred nineteen".
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