Base | Representation |
---|---|
bin | 1011101101111111001… |
… | …0011000011100100001 |
3 | 201020122112210011122102 |
4 | 2323133302120130201 |
5 | 11244302143201423 |
6 | 232253031020145 |
7 | 20354654311223 |
oct | 2733762303441 |
9 | 636575704572 |
10 | 201323022113 |
11 | 78420663304 |
12 | 3302680a655 |
13 | 15ca5457cb5 |
14 | 9a5bab6413 |
15 | 53846b0c28 |
hex | 2edfc98721 |
201323022113 has 2 divisors, whose sum is σ = 201323022114. Its totient is φ = 201323022112.
The previous prime is 201323022067. The next prime is 201323022119. The reversal of 201323022113 is 311220323102.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 198210163264 + 3112858849 = 445208^2 + 55793^2 .
It is a cyclic number.
It is not a de Polignac number, because 201323022113 - 218 = 201322759969 is a prime.
It is a super-2 number, since 2×2013230221132 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (201323022119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100661511056 + 100661511057.
It is an arithmetic number, because the mean of its divisors is an integer number (100661511057).
Almost surely, 2201323022113 is an apocalyptic number.
It is an amenable number.
201323022113 is a deficient number, since it is larger than the sum of its proper divisors (1).
201323022113 is an equidigital number, since it uses as much as digits as its factorization.
201323022113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 201323022113 its reverse (311220323102), we get a palindrome (512543345215).
The spelling of 201323022113 in words is "two hundred one billion, three hundred twenty-three million, twenty-two thousand, one hundred thirteen".
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