Base | Representation |
---|---|
bin | 1011101101111111011… |
… | …0000111001101101111 |
3 | 201020122121121212012120 |
4 | 2323133312013031233 |
5 | 11244302421000421 |
6 | 232253104004023 |
7 | 20354665523433 |
oct | 2733766071557 |
9 | 636577555176 |
10 | 201324000111 |
11 | 78421171073 |
12 | 33027000613 |
13 | 15ca570b1b0 |
14 | 9a5bc8c9c3 |
15 | 53848058c6 |
hex | 2edfd8736f |
201324000111 has 16 divisors (see below), whose sum is σ = 289992559584. Its totient is φ = 123500859264.
The previous prime is 201324000049. The next prime is 201324000181. The reversal of 201324000111 is 111000423102.
It is not a de Polignac number, because 201324000111 - 210 = 201323999087 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (201324000181) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8129836 + ... + 8154561.
It is an arithmetic number, because the mean of its divisors is an integer number (18124534974).
Almost surely, 2201324000111 is an apocalyptic number.
201324000111 is a deficient number, since it is larger than the sum of its proper divisors (88668559473).
201324000111 is a wasteful number, since it uses less digits than its factorization.
201324000111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16284730.
The product of its (nonzero) digits is 48, while the sum is 15.
Adding to 201324000111 its reverse (111000423102), we get a palindrome (312324423213).
The spelling of 201324000111 in words is "two hundred one billion, three hundred twenty-four million, one hundred eleven", and thus it is an aban number.
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