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20132403134001 = 36710801044667
BaseRepresentation
bin1001001001111011100001…
…01111001011111000110001
32122021122020210022121101120
410210331300233023320301
510114322130200242001
6110452410500452453
74145342501054544
oct444756057137061
978248223277346
1020132403134001
11646211679a324
1223119650aa129
13b30629000842
144d85b096085b
1524da53b8e236
hex124f70bcbe31

20132403134001 has 4 divisors (see below), whose sum is σ = 26843204178672. Its totient is φ = 13421602089332.

The previous prime is 20132403133963. The next prime is 20132403134029. The reversal of 20132403134001 is 10043130423102.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 20132403134001 - 243 = 11336310111793 is a prime.

It is not an unprimeable number, because it can be changed into a prime (20132403134401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3355400522331 + ... + 3355400522336.

It is an arithmetic number, because the mean of its divisors is an integer number (6710801044668).

Almost surely, 220132403134001 is an apocalyptic number.

It is an amenable number.

20132403134001 is a deficient number, since it is larger than the sum of its proper divisors (6710801044671).

20132403134001 is an equidigital number, since it uses as much as digits as its factorization.

20132403134001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6710801044670.

The product of its (nonzero) digits is 1728, while the sum is 24.

Adding to 20132403134001 its reverse (10043130423102), we get a palindrome (30175533557103).

The spelling of 20132403134001 in words is "twenty trillion, one hundred thirty-two billion, four hundred three million, one hundred thirty-four thousand, one".

Divisors: 1 3 6710801044667 20132403134001