Base | Representation |
---|---|
bin | 10010101111111111… |
… | …000010000010101001 |
3 | 1220222001200011100002 |
4 | 102233333002002221 |
5 | 312212343433132 |
6 | 13125415152345 |
7 | 1311620423345 |
oct | 225777020251 |
9 | 56861604302 |
10 | 20132405417 |
11 | 85a1244193 |
12 | 3a9a3756b5 |
13 | 1b8ac56237 |
14 | d8db10625 |
15 | 7cc6c2262 |
hex | 4affc20a9 |
20132405417 has 2 divisors, whose sum is σ = 20132405418. Its totient is φ = 20132405416.
The previous prime is 20132405401. The next prime is 20132405429. The reversal of 20132405417 is 71450423102.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11894301721 + 8238103696 = 109061^2 + 90764^2 .
It is a cyclic number.
It is not a de Polignac number, because 20132405417 - 24 = 20132405401 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 20132405417.
It is not a weakly prime, because it can be changed into another prime (20132405477) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10066202708 + 10066202709.
It is an arithmetic number, because the mean of its divisors is an integer number (10066202709).
Almost surely, 220132405417 is an apocalyptic number.
It is an amenable number.
20132405417 is a deficient number, since it is larger than the sum of its proper divisors (1).
20132405417 is an equidigital number, since it uses as much as digits as its factorization.
20132405417 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6720, while the sum is 29.
Adding to 20132405417 its reverse (71450423102), we get a palindrome (91582828519).
The spelling of 20132405417 in words is "twenty billion, one hundred thirty-two million, four hundred five thousand, four hundred seventeen".
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