Base | Representation |
---|---|
bin | 11101010010111110101… |
… | …100011001011101111101 |
3 | 21010110112102202222021221 |
4 | 131102332230121131331 |
5 | 230441110431113341 |
6 | 4140512125553341 |
7 | 265311030453202 |
oct | 35227654313575 |
9 | 7113472688257 |
10 | 2013244004221 |
11 | 7068a283421a |
12 | 28621b415851 |
13 | 117b04359668 |
14 | 6d6277b3ca9 |
15 | 37580a7bed1 |
hex | 1d4beb1977d |
2013244004221 has 4 divisors (see below), whose sum is σ = 2013395491744. Its totient is φ = 2013092516700.
The previous prime is 2013244004183. The next prime is 2013244004281. The reversal of 2013244004221 is 1224004423102.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 2013244004221 - 29 = 2013244003709 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2013244004281) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 75723825 + ... + 75750406.
It is an arithmetic number, because the mean of its divisors is an integer number (503348872936).
Almost surely, 22013244004221 is an apocalyptic number.
It is an amenable number.
2013244004221 is a deficient number, since it is larger than the sum of its proper divisors (151487523).
2013244004221 is a wasteful number, since it uses less digits than its factorization.
2013244004221 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 151487522.
The product of its (nonzero) digits is 3072, while the sum is 25.
Adding to 2013244004221 its reverse (1224004423102), we get a palindrome (3237248427323).
The spelling of 2013244004221 in words is "two trillion, thirteen billion, two hundred forty-four million, four thousand, two hundred twenty-one".
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