Base | Representation |
---|---|
bin | 11101010010111110101… |
… | …100110110011010111011 |
3 | 21010110112102222222222011 |
4 | 131102332230312122323 |
5 | 230441110443412221 |
6 | 4140512132310351 |
7 | 265311031456015 |
oct | 35227654663273 |
9 | 7113472888864 |
10 | 2013244122811 |
11 | 7068a2905329 |
12 | 28621b4723b7 |
13 | 117b0439b62c |
14 | 6d6278051b5 |
15 | 37580aa21e1 |
hex | 1d4beb366bb |
2013244122811 has 2 divisors, whose sum is σ = 2013244122812. Its totient is φ = 2013244122810.
The previous prime is 2013244122787. The next prime is 2013244122881. The reversal of 2013244122811 is 1182214423102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2013244122811 - 211 = 2013244120763 is a prime.
It is not a weakly prime, because it can be changed into another prime (2013244122881) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006622061405 + 1006622061406.
It is an arithmetic number, because the mean of its divisors is an integer number (1006622061406).
Almost surely, 22013244122811 is an apocalyptic number.
2013244122811 is a deficient number, since it is larger than the sum of its proper divisors (1).
2013244122811 is an equidigital number, since it uses as much as digits as its factorization.
2013244122811 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6144, while the sum is 31.
Adding to 2013244122811 its reverse (1182214423102), we get a palindrome (3195458545913).
The spelling of 2013244122811 in words is "two trillion, thirteen billion, two hundred forty-four million, one hundred twenty-two thousand, eight hundred eleven".
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