Base | Representation |
---|---|
bin | 111011111111111… |
… | …1111111111110011 |
3 | 12012022022111121222 |
4 | 1313333333333303 |
5 | 13110344002112 |
6 | 531435135255 |
7 | 100614322622 |
oct | 16777777763 |
9 | 5168274558 |
10 | 2013265907 |
11 | 943488524 |
12 | 4822a452b |
13 | 261140603 |
14 | 15154d6b9 |
15 | bbb33372 |
hex | 77fffff3 |
2013265907 has 2 divisors, whose sum is σ = 2013265908. Its totient is φ = 2013265906.
The previous prime is 2013265901. The next prime is 2013265921. The reversal of 2013265907 is 7095623102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2013265907 - 28 = 2013265651 is a prime.
It is a super-2 number, since 2×20132659072 = 8106479224577065298, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2013265901) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006632953 + 1006632954.
It is an arithmetic number, because the mean of its divisors is an integer number (1006632954).
Almost surely, 22013265907 is an apocalyptic number.
2013265907 is a deficient number, since it is larger than the sum of its proper divisors (1).
2013265907 is an equidigital number, since it uses as much as digits as its factorization.
2013265907 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 22680, while the sum is 35.
The square root of 2013265907 is about 44869.4317659584. The cubic root of 2013265907 is about 1262.7005793394.
The spelling of 2013265907 in words is "two billion, thirteen million, two hundred sixty-five thousand, nine hundred seven".
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