Base | Representation |
---|---|
bin | 11101010011000010101… |
… | …100010110110001001011 |
3 | 21010110201010000220011212 |
4 | 131103002230112301023 |
5 | 230441230120231102 |
6 | 4140522524043335 |
7 | 265312504001501 |
oct | 35230254266113 |
9 | 7113633026155 |
10 | 2013311102027 |
11 | 7069276a2855 |
12 | 28623999354b |
13 | 117b152201c4 |
14 | 6d63267c671 |
15 | 375868d2c52 |
hex | 1d4c2b16c4b |
2013311102027 has 2 divisors, whose sum is σ = 2013311102028. Its totient is φ = 2013311102026.
The previous prime is 2013311101999. The next prime is 2013311102063. The reversal of 2013311102027 is 7202011133102.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2013311102027 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2013311101993 and 2013311102011.
It is not a weakly prime, because it can be changed into another prime (2013311122027) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006655551013 + 1006655551014.
It is an arithmetic number, because the mean of its divisors is an integer number (1006655551014).
Almost surely, 22013311102027 is an apocalyptic number.
2013311102027 is a deficient number, since it is larger than the sum of its proper divisors (1).
2013311102027 is an equidigital number, since it uses as much as digits as its factorization.
2013311102027 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 504, while the sum is 23.
Adding to 2013311102027 its reverse (7202011133102), we get a palindrome (9215322235129).
The spelling of 2013311102027 in words is "two trillion, thirteen billion, three hundred eleven million, one hundred two thousand, twenty-seven".
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