2013311320133 has 4 divisors (see below), whose sum is σ = 2025662923488. Its totient is φ = 2000959716780.

The previous prime is 2013311320127. The next prime is 2013311320247. The reversal of 2013311320133 is 3310231133102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2013311320133 - 2¹⁰ = 2013311319109 is a prime.

It is a super-2 number, since 2×2013311320133² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2013311320099 and 2013311320108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2013311320633) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6175801433 + ... + 6175801758.

It is an arithmetic number, because the mean of its divisors is an integer number (506415730872).

Almost surely, 2^{2013311320133} is an apocalyptic number.

It is an amenable number.

2013311320133 is a deficient number, since it is larger than the sum of its proper divisors (12351603355).

2013311320133 is a wasteful number, since it uses less digits than its factorization.

2013311320133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12351603354.

The product of its (nonzero) digits is 972, while the sum is 23.

Adding to 2013311320133 its reverse (3310231133102), we get a palindrome (5323542453235).

The spelling of 2013311320133 in words is "two trillion, thirteen billion, three hundred eleven million, three hundred twenty thousand, one hundred thirty-three".