Base | Representation |
---|---|
bin | 1001001001111100110111… |
… | …00110101010011010010011 |
3 | 2122021201002220121001010202 |
4 | 10210332123212222122103 |
5 | 10114330113303220034 |
6 | 110453010111245415 |
7 | 4145366353045022 |
oct | 444763346523223 |
9 | 78251086531122 |
10 | 20133122320019 |
11 | 6462455753435 |
12 | 2311b25b1986b |
13 | b30711cc99b7 |
14 | 4d863c2908b9 |
15 | 24da96da147e |
hex | 124f9b9aa693 |
20133122320019 has 2 divisors, whose sum is σ = 20133122320020. Its totient is φ = 20133122320018.
The previous prime is 20133122319883. The next prime is 20133122320043. The reversal of 20133122320019 is 91002322133102.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-20133122320019 is a prime.
It is a super-2 number, since 2×201331223200192 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 20133122319973 and 20133122320000.
It is not a weakly prime, because it can be changed into another prime (20133122320049) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10066561160009 + 10066561160010.
It is an arithmetic number, because the mean of its divisors is an integer number (10066561160010).
Almost surely, 220133122320019 is an apocalyptic number.
20133122320019 is a deficient number, since it is larger than the sum of its proper divisors (1).
20133122320019 is an equidigital number, since it uses as much as digits as its factorization.
20133122320019 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3888, while the sum is 29.
The spelling of 20133122320019 in words is "twenty trillion, one hundred thirty-three billion, one hundred twenty-two million, three hundred twenty thousand, nineteen".
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