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201331233012000 = 253537133727717989
BaseRepresentation
bin101101110001110000010100…
…101000000011100100100000
3222101212002002210101220122210
4231301300110220003210200
5202342102331122341000
61552110142553002120
760256462432235220
oct5561602450034440
9871762083356583
10201331233012000
1159172107382753
121a6b74126b3340
1388455b90307c0
1437a06ab29c080
151842149e9a350
hexb71c14a03920

201331233012000 has 1536 divisors, whose sum is σ = 836763480483840. Its totient is φ = 41179108147200.

The previous prime is 201331233011999. The next prime is 201331233012023. The reversal of 201331233012000 is 210332133102.

It is a super-2 number, since 2×2013312330120002 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (21).

It is an unprimeable number.

It is a polite number, since it can be written in 255 ways as a sum of consecutive naturals, for example, 11191899006 + ... + 11191916994.

It is an arithmetic number, because the mean of its divisors is an integer number (544767890940).

Almost surely, 2201331233012000 is an apocalyptic number.

201331233012000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 201331233012000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (418381740241920).

201331233012000 is an abundant number, since it is smaller than the sum of its proper divisors (635432247471840).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

201331233012000 is a wasteful number, since it uses less digits than its factorization.

201331233012000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 18351 (or 18333 counting only the distinct ones).

The product of its (nonzero) digits is 648, while the sum is 21.

Adding to 201331233012000 its reverse (210332133102), we get a palindrome (201541565145102).

The spelling of 201331233012000 in words is "two hundred one trillion, three hundred thirty-one billion, two hundred thirty-three million, twelve thousand".